How Every Unit Relates
\[ T = F\,r,\qquad T_{\text{unit}} = \frac{T_{\text{N}\cdot \text{m}}}{k_{\text{unit}}} \]
\[ 1\ \text{lbf}\cdot \text{ft} = 1.355818\ \text{N}\cdot \text{m} \]
\[ 1\ \text{kgf}\cdot \text{m} = 9.80665\ \text{N}\cdot \text{m} \]
Torque is a force times a length. So each unit is a force unit times a length unit. Its size in N·m, in the right-hand column, is the force factor times the length factor.
A pound-force is 4.448222 N and a foot is 0.3048 m, so a pound-foot is 4.448222 × 0.3048 = 1.355818 N·m. The converter turns your number into N·m, then divides by each unit’s size.
Energy per angle
\[ T = \frac{dE}{d\theta}\qquad\Rightarrow\qquad 1\ \text{N}\cdot \text{m} = 1\ \text{J/rad} \]
\[ 1\ \text{J/rev} = \frac{1}{2\pi}\ \text{N}\cdot \text{m} \]
Torque is also the energy a rotation transfers per unit of angle. A radian is dimensionless, so a joule per radian is the same as a newton-metre. A joule per degree is 57.3 times larger, because a degree is a smaller angle.
This is how torque reaches the atomic scale. The atomic unit of torque is a hartree of energy per radian, and an electronvolt per radian is 1.6×10−19 N·m. A molecular motor turning a flagellum is in the tens of piconewton-nanometres.
Watch the pound. The pound in lbf·ft is the pound-force. The poundal-foot, by contrast, uses the poundal, the force that accelerates one pound of mass at one foot per second squared, which is about 0.138 N.
The page also treats kgf·m as kilogram-force metres, the way older torque tables and some wrenches use it.